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    Question

    I. x2 - 5x - 14 = 0 II.

    y2 - 16y + 64 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A if x>y Correct Answer Incorrect Answer
    B if x Correct Answer Incorrect Answer
    C if x≥y Correct Answer Incorrect Answer
    D if x≤y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    I. x2 - 5x - 14 = 0 => x2 - 7x + 2x - 14 = 0 => x(x - 7) + 2(x - 7) = 0 => (x - 7) (x + 2) = 0 => x = 7, -2 II. y2 - 16y + 64 = 0 => y2 - 8y - 8y + 64 = 0 => y(y - 8) - 8(y - 8) = 0 => (y - 8) (y - 8) = 0 => y = 8, 8 Hence, x < y.

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