Question
I. 5q = 7p + 21 II. 11q + 4p + 109 =
0 In each of these questions two equations numbered I and II are given. You have to solve both the equations and give answer, if –Solution
I. 5q = 7p + 21 5q - 7p = 21 II. 11q + 4p + 109 = 0 11q + 4p = - 109 Solving equation (i) x 11 and (ii) x 5 p = - 8 and q = - 7 Hence p < q
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