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    Question

    A bag contains 3 black balls, 12 blue balls, and 3

    yellow balls. Two balls are drawn at random. Find the probability that the two balls are blue.
    A 22/51 Correct Answer Incorrect Answer
    B 4/17 Correct Answer Incorrect Answer
    C 8/51 Correct Answer Incorrect Answer
    D 16/51 Correct Answer Incorrect Answer

    Solution

    Number of ways of selecting two blue balls = 12 CтВВ
    Total number of balls = 3 + 12 + 3 = 18

    Number of ways of selecting two balls = 18 CтВВ
    Probability = 12 CтВВ ├╖ 18 CтВВ = (12 ├Ч 11) ├╖ (18 ├Ч 17) = 132 ├╖ 306 = 22/51

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