Question
If four pencils are picked at random, what is the
probability that one is green, two are blue and one is red? Â A box contains 6 red, 4 blue, 2 green and 4 yellow pencils.ÂSolution
Total pencils = 6R + 4B + 2G + 4Y = 16 We need: 1 green, 2 blue, 1 red in 4 draws (order doesn’t matter). Favourable ways = C(2,1) · C(4,2) · C(6,1) = 2 · 6 · 6 = 72 Total ways to choose 4 from 16 = C(16,4) = 1820 Required probability = 72 / 1820 = 18 / 455.
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