Question
The ratio of the current ages of ‘A’ and ‘B’ is
4:7, while the ratio of the current ages of ‘B’ and ‘C’ is 3:2. If the difference between the present ages of ‘B’ and ‘A’ is 18 years, determine the age of ‘C’ five years ago.Solution
ATQ,
Let the present age of ‘B’ be 7x years. So, the present age of ‘A’ = (4/7) × 7x = 4x years The present age of ‘C’ = (2/3) × 7x = (14x/3) years According to the given information: 7x - 4x = 18 ⇒ x = 6 So, present age of ‘C’ = (14/3) × 6 = 28 years Age of ‘C’ five years ago = 28 - 5 = 23 years
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