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Number of chocolates distributed in class V = (32/100) × 2500 = 800 Number of chocolates distributed in class III and VI together = (25 + 10)% of 2500 = 875 Required difference = [(875 – 800)/875] × 100 = 9% less (approx.)
If tan θ = 4/3 and θ is an acute angle, find the value of sin θ + cos θ.
If (sinθ+cosθ)/(sinθ-cosθ) = 2, then the value of sin4 θ is
If tanθ = (2/√5), then find the value of cos2 θ
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
Take θ = 450
If cos²α + cos²β = 2, then the value of tan⁴α + sin⁸β is