Question
What is the Probability of getting a sum of
‘9’ on rolling a dice twice?Solution
Now, the concerned events should have sum of ‘9’ i.e., number on Dice 1 + number on Dice 2 = 9 This can be seen in three cases: (3,6) , (6,3) , (4,5) , (5,4) So Concerned events = 4 And, we know total events are always ‘36’ So, Probability = 4/36= 1/9
If (tan 8θ · tan 2θ = 1), then find the value of (tan 10θ).
If 17sin A = 8, where 0
- If sin(A + B) = 1/2 and cos(A + 2B) = √3/2, where 0° < A, B < 90°, then find the value of tan(2A).
[(sinx – 2sin 3 x)/(2cos 3 x – cosx)] 2  + 1, x ≠45 o , is equal to:
If cos2B = sin(1.5B + 41o), then find the measure of 'B'.
- Simplify the following trigonometric expression:
15 cos 27° sec 63° − 9 cot 61° tan 29° The value of (3tan10°-tan³10°)/(1-3tan²10°) is equal to
Find the value of sin 240 °