Question
The smallest number which when added to 10000 becomes
divisible by 20, 24 and 30 isSolution
ATQ,
First, find LCM of 20, 24, and 30: Prime factors: 20 = 2² × 5 24 = 2³ × 3 30 = 2 × 3 × 5 ⇒ LCM = 2³ × 3 × 5 = 120 Now divide 10000 by 120: 10000 ÷ 120 = 83 remainder 40 So, we need to add (120 - 40) = 80 to make it divisible
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