Question
The mean proportion of (3+2√2) and (3–2√2)
is:Solution
b be the mean proportional 3+2√2: b: b: 3-2√2 Product of means = Product of extremes B × b = (3 + 2√2) (3 - 2√2) b² = (3) ² - (2√2) ² - b² = 9 - (4 x 2) b² = 9-8 b² = 1 Taking square roots on both sides: √b² = √1 b = ± 1
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