Question
The mean proportion of (3+2β2) and (3β2β2) is:
Solution
b be the mean proportional 3+2β2: b: b: 3-2β2 Product of means = Product of extremes B Γ b = (3 + 2β2) (3 - 2β2) bΒ² = (3) Β² - (2β2) Β² - bΒ² = 9 - (4 x 2) bΒ² = 9-8 bΒ² = 1 Taking square roots on both sides: βbΒ² = β1 b = Β± 1
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