Question
If the cube with a 26β3 cm diagonal is melted then how
tall is the height of the cuboid, if the length of the cuboid is equal to the arm of the cube, and the width of the cuboid is 13 cm? (in cm)Solution
As we know, The volume of cube = aΒ³ The volume of cuboid = lbh Diagonal of the cube = β3a β3a = 26β3 Β a = 26 Length of the cuboid I = 26 cm Β Let the height of the cuboid be h cm Width of the cuboid b = 13 cm According to the question- Β 26 x 13 x h = 26 x 26 x 26 h = (26 x 26 x 26) / (26 x 13) h = 52 cm.
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