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    Question

    A man had to travel 49 km, which he divided into six

    stretches which were exact multiples of either 4 km or 5 km. The first four stretches were 4 km 5 km, 8 km and 10 km. Multiples of 4 km and 5 km were travelled at the rates of 40 and 60 km/h, respectively, and between two consecutive stretches, he rested for six minutes. What was his average speed (in km/h) for the whole journey?
    A 31(7/11) Correct Answer Incorrect Answer
    B 32(4/13) Correct Answer Incorrect Answer
    C 33(3/8) Correct Answer Incorrect Answer
    D 34(4/15) Correct Answer Incorrect Answer

    Solution

    Remaining distance = 49 - (4 + 5 + 8 + 10) тЗТ 22 km Only 12 km and 10 km is possible according to the question, Total time taken to complete the journey = (4/40 + 5/60 + 8/40 + 10/60 + 12/40 + 10/60)h + 6 ├Ч 5 m [Total 5 times halt of 6 minutes each] тЗТ (1/10 + 1/12 + 1/5 + 1/6 + 3/10 + 1/6)h + 30 m тЗТ (6 + 5 + 12 + 10 + 18 + 10)/60 + 1/2 тЗТ 61/60 + 1/2 тЗТ 91/60 hours Average speed = 49 ├Ч 60/91 тЗТ 420/13 тЗТ 32(4/13) тИ┤ His average speed (in km/h) for the whole journey was 32(4/13).

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