Question
A can complete a piece of work in 10 days. B is 25% more
efficient than A. How many days will B alone take to complete the same work?Solution
Let A's efficiency is 4a. So, B's efficiency = 4a + 4a x 25%=5a Now, total work = 4a x 10=40a So, B will take to complete the task = 40a/5a = 8 days B alone will take 8 days to complete the same work.
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