Question
Manoj can complete a work in 15 days working 8 hours in
a day and Santosh can complete it in 10 days working 9 hours in a day. If Manoj and Santosh together start working for 6 hours per day, in how many days will they complete the work?Solution
Let the efficiency of Manoj be M and that of Santosh be S. Total work to be done (according to Manoj) = 15 × M × 8  Total work to be done (according to Santosh) = 10 × S × 9 Work done by both are the same, => 15 × M × 8 = 10 × S × 9 => M/S = 3/4 Let the efficiency of Manoj and Santosh be 3 and 4 respectively. Working together, total efficiency = 3 + 4 = 7 Let them finish the work by D days. Total work to be done = 15 × M × 8 = 15 × 3 × 8 => 7 × D × 6 = 15 × 3 × 8 Time taken = 360/42 = 8 (4/7) days
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
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