Question
k is the greatest number which, when divided 2996, 4752,
and 7825, the remainder in each case is the same. The product of the digits of k is.Solution
According to the question (7825-4752) = 3073 (7825-2996) = 4829 (4752-2996) = 1756 Now, HCF of 3073, 4829 and 1756 is. 3073 = 7 x 439 4829 =11 × 439 1756 = 2 x 2 x 439 So, k = 439 Now, The product of the digits of k = (4 x 3 x 9) =108.
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