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    Question

    The population of a town is 10,000. If the male

    population increases by 5% and the female population by 10%, the population will become 10,800. How much of the town's present population is female?
    A 5000 Correct Answer Incorrect Answer
    B 8000 Correct Answer Incorrect Answer
    C 6000 Correct Answer Incorrect Answer
    D 7000 Correct Answer Incorrect Answer

    Solution

    Let the number of men =x Female =10,000-x ATQ- 5x+100000-10x =80000. -5x =2000 X =4000. Female =10000-4000=6000. Second method- Let the number of males =100x And female =100y ATQ- x+y =100        … (1) ×5 5x+10y =800             … (2) 5x+5y =500               … (3) Solving EQ (1) and EQ (2). 5y =300 Y=60. Number of females =100×60 =6000.

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