Question
The shadow of a tower on ground level is increased by 30
m, when the angle of depression by the sun changes from 60° to 30º. The height of the tower is?Solution
ATQ- Tan 60° = h / x h= √3x … (1). Tan30° = h/(x+30) 1/√3 =h/x+30 h = (x+30)/√3 … (2) EQ (1) and Eq (2) both are equal. √3x =(x+30)/√3 3x =x+30 2x =30 X=15. Now put the value of x in equation (1). Height =15√3 m. 
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