Question
Find the value of x if 0.08x+0.04y=10 and
0.2(x-1)+0.4y=24.8Solution
0.08x+0.04y=10 8x+4y =1000 2x+y=250 Y =250-2x… (1) 0.2(x-1) +0.4y=24.8 2(x-1) +4y=248 2x-2+4y =248 2x+4y=250put the value of Y 2x +4(250-2x) =250 2x +1000-8x =250 6x =750 X =125.
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