Question
Reena reaches a party 20 minutes late if she walks at
the speed of 3 km/h from her house. If she increases her speed to 4 km/h, she will reach 30 minutes early What is the distance between her home and the venue?Solution
ATQ, Let distance = x km. Time taken at 3 kmph : dist/speed = x/3 = 20 min late. time taken at 4 kmph : x/4 = 30 min earlier difference between time taken : 30-(-20) = 50 mins = 50/60 hours. x/3- x/4 = 50/60 x/12 = 5/6 x = 10 km.
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