Question
Solution
Given, a/b + b/a = -1 a2 + b2 = -ab a2 + b2 + ab = 0 we know that, a3 - b3 = (a - b)(a2 + b2 + ab) a3 - b3 = (a - b) × 0 a3 - b3 = 0 So, 6(a3 - b3) = 0
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