Question
Solution
Given, a/b + b/a = -1 a2 + b2 = -ab a2Ā + b2Ā + ab = 0 we know that, a3 - b3 = (a - b)(a2 + b2 + ab) a3Ā - b3Ā = (a - b) Ć 0Ā a3Ā - b3Ā = 0 So, 6(a3Ā - b3)Ā = 0
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