Question
What is the least number of three digits, which when
divided by 6, 12 and 15 leaves no remainder?Solution
6 = 2 × 3 12 = 2 × 2 × 3 15 = 3 × 5 LCM (6, 12, 15) = 3 × 2 × 2 × 5 = 60 any multiple of 60 is divisible by 6, 12, 15 without leaving any remainder. ⇒ Hence, 120 is the least number of options that satisfy our condition.
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