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Let the four angles of a quadrilateral are (a−3d)°, (a−d)°, (a+d)° and (a+3d)° a−3d+a−d+a+d+a+3d=360° => a = 90° But the greatest angle is double the least, i.e., a+3d=2×(a−3d)=2a−6d 9d=2a−a=a=90° d = 90/9 = 10° Least angle a−3d=90°−3×10°= 60°
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