Question
A speaks the truth 5 out of 7 times and B speaks truth 8
out of 9 times. What is the probability that they contradict each other in stating the same fact?Solution
ATQ, Probability that A speak Truth, P(A) = (5/))) Probability that B speak Truth, P(B) = (8/9) Probability that A and B lie is P(A) lies=1/7  P(B) lies=1/9 Required probability = P(A)×P(B)+P(A)×P(B) = {[(5/7) × (1/9)] + [(1/7) × (8/9)]]} = (5/63) + (8/63) = 13/63
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