Question
Pipe ‘A’ and pipe ‘B’ can fill a tank alone in
45 hours and 15 hours, respectively. If both pipes are opened together and pipe ‘B’ is closed after 6 hours, then find the time taken by pipe ‘A’ to fill the remaining portion of the tank alone.Solution
Let the capacity of the tank be 45 units (LCM of 45 and 15) Efficiency of pipe ‘A’ = 45 ÷ 45 = 1 unit/hour
Efficiency of pipe ‘B’ = 45 ÷ 15 = 3 unit/hour Let pipe ‘A’ fill the remaining portion in x hours. ATQ, 6 × (1 + 3) + 1x = 45 Or, 24 + x = 45 Or, x = 21 Therefore, required time taken = 21 hours
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