Two pipes A and B can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 minutes?
Let total capacity of cistern = LCM(24, 32 ) = 96 L So A can fill in 1 min = 96/24 = 4L & B can fill in 1 min = 96/32 = 3L Now B is left in between , it means A is opened all time. So in 18 min, A can fill = 18 × 4 = 72L So remaining tank = 96 – 72 = 24L So B can do it in = 24/3 = 8 min
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