There was the leakage in the refined container. If 8 litre of refined is leaked out per day then it would have lasted for 20 days and if the leakage was 12 litre per day, then it would have lasted for only 16 days. For how many days would the refined have lasted if there is no leakage and it was completely used for consumption?

Let x kg of Refined is used for daily consumption, then (x + 8) × 20 = (x + 12) × 16 20x + 160 = 16x + 192 4x = 32 x = 8 ∴ Total quantity of Oil = (8 + 8) × 20 = 320 litre Required number of Days = 320/8 = 40 days

- Pipes ‘A’ and ‘B’ can fill a tank in 6 hours and 9 hours, respectively. If pipe ‘C’ is opened along with pipes ‘A’ and ‘B’, then the tank gets filled in 4.5 hours. Find the time taken by pipe ‘C’ to empty (2/3)th part of the same tank.
- Pipe ‘A’ and pipe ‘B’, together can fill 32% of a tank in 8 hours while pipe ‘C’ takes 35 hours to empty it. Pipe ‘A’ and pipe ‘B’ were opened together. After 24 hours, pipe ‘C’ is also opened. Find the total time taken to fill the empty tank this way.
- Two inlet pipes M and N alone can fill a tank in 12 hours and 16 hours respectively and an outlet pipe P alone can empty the whole tank in 8 hours. First pipe M is opened for 6 hours, then pipe P is opened for 4 hours and rest of the tank is filled by pipe N. In what time will the tank be filled completely?
- There are 16 taps which are fitted in a tank .In which some are inlet pipes and some are Outlet pipes .Each inlet tap has the efficiency to fill the tank in 12 hours and each outlet tap can empty the tank in 8 hours .If all the pipes are kept open when the tank is full it will take exactly 8 hours for the tank to empty. Then find how many of these are inlet pipes?
- Pipe ‘A’ can fill 25% of a tank in 6 hours while pipe ‘B’ takes 40 hours to empty fully filled tank. Pipe ‘A’ is opened alone when the tank was empty. After 12 hours, pipe ‘B’ is also opened. In how much time the tank will get filled this way?
- Two pipes P1 and P2 can fill a cistern in 12 minutes and 15 minutes respectively. These pipes are opened alternately for 1 minute each, beginning with pipe P1. In what time will the cistern be full?
- Two inlet pipes M and N alone can fill a tank in 10 hours and 12 hours respectively and an outlet pipe P alone can empty the whole tank in 8 hours. First pipe M is opened for 5 hours, then pipe P is opened for 2 hours and rest of the tank is filled by pipe N. In what time will the tank be filled completely?
- There are two pipes A & B, pipe A is for filling the swimming pool and pipe B is to empty the swimming pool. Capacity of swimming pool is 15120 m
^{3}and volume of pipe B is 24 m^{3 }/minute more than that of pipe A. If pipe A takes 11(1/4) more minutes to fill same swimming pool, than time taken by B to empty the same swimming pool. If pipe B can empty second swimming pool in 102.5 minutes, then find the capacity of second swimming pool? - Pipe ‘A’ can fill a 210-litre tank in 15 hours. If pipe ‘A’ is 25% more efficient than pipe ‘C’ whereas pipe ‘B’ is 50% more efficient than pipe ‘C’, then find the time (in minutes) taken by all the given three pipes to fill the same tank together.
- Two pipes A and B can fill a tank in 12 min., and 16 min, respectively. If both the pipes are opened simultaneously, after how much time A should be closed so that the tank is full in 12 minutes?

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