Question
How many 5-digit numbers can be formed using digits
1–7 such that digits are odd-even-odd-even-odd?Solution
ATQ,
Odd digits = 1,3,5,7 = 4; Even = 2,4,6 = 3. Pattern: O-E-O-E-O → 3 odd used, 2 even used. Odd: 4P3 = 24, Even: 3P2 = 6 → Total = 24×6=144 → 144 numbers.
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