Question
How many 5-digit numbers can be formed using digits
1–7 such that digits are odd-even-odd-even-odd?Solution
ATQ,
Odd digits = 1,3,5,7 = 4; Even = 2,4,6 = 3. Pattern: O-E-O-E-O → 3 odd used, 2 even used. Odd: 4P3 = 24, Even: 3P2 = 6 → Total = 24×6=144 → 144 numbers.
- Find the simplified value of the given expression.

What will come in the place of question mark (?) in the given expression?
(72 × 4 – 92) ÷ 14 = ?
1300% of 2341 + 1200% of 6321 = ?
135 ÷ 3 of 5 = ? - 112
[4(1/2) + 4(1/3)] × 12 – 42 = ?2
If √3n 729, then the value of n is equal to:
25% of 140 + 2 × 8 = ? + 9 × 5
Simplify:
0.48 ÷ 0.06 + 0.75 × (4/5)
[∛(3375/19683  )- ∛(125/1728  )  ] ÷ ∛(64/729)  = ? - 3/8Â
72 × 2 = ? + 104 – 14