Question
A team of 10 members is to be formed from 9 engineers and 6
doctors. Find the number of ways the team can be formed with at least 8 engineers.Solution
Case I: 8 engineers and 2 doctors
Number of ways = 9C8 × 6C2 = 9 × 15 = 135 ways
Case II: 9 engineers and 1 doctor
Number of ways = 9C9 × 6C1 = 1 × 6 = 6 ways
Total number of ways = 135 + 6 = 141 ways
If the sum of three numbers is zero, then which of the options below will always be equal to the value of the sum of the cubes of those numbers?
In Δ ABC, ∠ B= 68° and ∠ C 32°. Sides AB and AC are produced to points D and E, respectively. The bisectors of ∠ DBC and ∠...
Find the value of
(1 - Â `1/(p+1)` ) + (1 - `2/(p+1)` Â ) + (1 - `3/(p+1)` Â ) + ........................... + (1 - Â `p/(p+1)` )
If
= 2 then find If 3x + (1/3x) = 9 then find 27x³ + (1/27x³ ) = ?
if a2 + b2 + c2Â =Â 2(3a -5b -6c)-70 , then a-b-c = ?
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If Â
 = 4 then ![](ht...</a></li> <div class="clearfix mt-3"></div>
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