Question
A team of 10 members is to be formed from 9 engineers and 6
doctors. Find the number of ways the team can be formed with at least 8 engineers.Solution
Case I: 8 engineers and 2 doctors
Number of ways = 9C8 × 6C2 = 9 × 15 = 135 ways
Case II: 9 engineers and 1 doctor
Number of ways = 9C9 × 6C1 = 1 × 6 = 6 ways
Total number of ways = 135 + 6 = 141 ways
In how ways can the selection be made so that a particular member is always excluded?
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