Question
A committee of 5 members is to be selected from 4 girls and
6 boys. Find the number of ways to form team such that the team consists of at most 2 girls.Solution
Required number of ways = 4C2 × 6C3 + 4C1 × 6C4 + 6C5
= 6 × 20 + 4 × 15 + 6
= 120 + 60 + 6 = 186
20.05% of 150.05 – 12.15% of 99.99 × 2.02 = ?
(?)2 + 8.113 = 28.92 – 73.03Â
11.89 × 2.10 × 4.98 × 4.03 ÷ 7.98 of 15.03 = ?
(?)2 + 4.113 = 23.92 – 28.03
25.11% of 199.99 + √143.97 ÷ 6.02 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`(601/49)xx(399/81)` ÷ `(29/201)` = ?
(10.013 – 12.04) = ? + 7.98% of 4999.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....