Question
A group consists of 10 boys and 6 girls. In how many ways
can 6 boys and 2 girls be selected from the group?Solution
Required number of ways = 10 C 6 × 6 C 2
= (10! / (6! × 4!)) × (6! / (2! × 4!))
= 210 × 15 = 3,150
Conclusions:
I. Some Signs are Symbols.
II. Some Signs are not Marks.
III. No Number is a Mark.
Statements:
Statements:
Only a few ST are GY
A few VB are GY
Only VB are AZ
Conclusions:
I. A few VB are not GY
II. All ST can never be VB
III. No AZ is GY
Statements: Â Â Â Â Â All phones are battery.
                            No battery is a network.
  ...
Statements:
All clubs are pub.
No pub is a song.
All songs are music.
Conclusions:
I. All songs being...
In the questions given below there are three statements followed by three conclusions I, II and III. You have to take the three given statements to be ...
In the question below there are three statements followed by two conclusions I and II. You have to take the three given statements to be true even if t...
In the following question below are given some statements followed by some conclusions based on those statements. Taking the given statements to be tru...
In the question below some statements are given followed by three conclusions I, II and III. You have to take the given statements to be true even if ...
Statements:
All Surfaces are Measurements.
Only few Measurements are Values.
Only few Values are Result.
No Result is a Co...
Statements :
Some pens are tables.
No table is a book.
Some books are threads
Some threads are boxes.
Conclusions: ...
Relevant for Exams:
