Question
A town’s population increases by 10% in the first year
and by 20% in the second year. If the population at the end of the second year is 39,600, find the population at the beginning of the first year.Solution
Overall factor = 1.10 × 1.20 = 1.32 Let initial population = P P × 1.32 = 39,600 P = 39,600 / 1.32 1.32 = 132/100 P = 39,600 × 100 / 132 = 3,960,000 / 132 132 × 30,000 = 3,960,000 So P = 30,000 Answer: Initial population = 30,000.
More Percentage Questions
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4 What will come in the place of question mark (?) in the given expression?
√4096 + √3249 = (?)2
Simplify the following expressions and choose the correct option.
 (96 ÷ 8 + 72 ÷ 9) * 3
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
{(5/8) + (4/5)} × (?/19) = 33
(72 × 52 + 1555 )/(79+60) = 2000 ÷ ?
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2Â
- What will come in place of (?) in the given expression.
(14)² – (12)² = ? What value should come in the place of (?) in the following questions?
√(60 + 82 + 101) * 5 = ?
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