A and B together have total of Rs.4200 out of which they donated 10% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/7) + 21].
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 4200 x 0.90 => 2.4P = 3780 => P = 1575 Share of A = 3780 – 1575 = Rs.2205 So, 3X = 2205 => X = 735 Required value = [(X/7) + 21] = 105 + 21 = 126
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