Question
A and B together have total of Rs.4200 out of which they
donated 10% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/7) + 21].Solution
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 4200 x 0.90 => 2.4P = 3780 => P = 1575 Share of A = 3780 – 1575 = Rs.2205 So, 3X = 2205 => X = 735 Required value = [(X/7) + 21] = 105 + 21 = 126
More Percentage Questions
Evaluate:
7.5 + 12 ÷ (4 × 1.5) − 2.4
22% of 560 + 34% of 2160 × 5/12 =? + 16% of 920
(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
10³ = (? – 6) × 320 ÷ 8
7(3/6) of 534 + 262 = 61800 - ?
(150% of 950) ÷ ? = 25
181/8 + 51/4 – 63/8 = ? + 9/2
34 × 5 × 2 ÷ 6 + 7 × 5 + 13 = (?)× 6 – 754
What will come in the place of question mark (?) in the given expression?
?% of 2480 + 15 × 34 = 1440
