Question
The speed of A is 20% more than B, and the speed of C is
80 more than the difference of the speeds of A and B. If C’s speed is 140, then find the speed of A.Solution
ATQ, Let the speed of B be x. So, speed of A = 1.20x According to question, (1.20x – x) + 80 = 140 0.20x = 140 – 80 0.20x = 60 x = 60 / 0.20 x = 300 Therefore, speed of A = 1.20 × 300 = 360
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