75% of A is equal to 40% of C and 80% of B is equal to 100% of A. If sum of 50% of B and 30% of C is equal to 95, then find 80% of A.
Let A be 100x. So, C = (75/100) × 100x × (100/40) = 375x /2 And, B = 100x × (100/80) = 125x According to the question, => (50/100) × 125x + (30/100) × (375x/2) = 95 => 62. 5x + 56.25x = 95 => x = 0.8 Required value = (80/100) × 100 × 0.8 = 64
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