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Number of students who like samosa only = 520 × 0.30 = 156 Number of students who like samosa and momos both = 520 × 0.4 = 208 Number of students who don’t like any snacks = 520 × 0.20 = 104 Number of students who like momos only = 520 – 156 – 208 – 104 = 52
√(24²+285-8²-172) = ?²
289 + 896 + 144 – 25% of 1100 =?
60 = (? x 10 + 250)/5
Find the value of ‘y’ if (2/7) × y = 0.79 – 1.77 ÷ 3.
24% of 15% of 500 + 122 = ?2 – (232 ÷ 2)
`sqrt(5476)` + 40% of 1640 = ?`xx` 4 - 2020
Determine the value (6.375)2 - (3.125)2
The value of 97 × 103 is _________.
24% of 400 × 16% of ? = 384
Find the value of 'p' in the given expression: 15 of 6 ÷ p x 4 = 30.