Question
A man donated 20%, 15% and 24% of his income to three
NGOs βAβ, βBβ and βCβ, respectively. They spent 75%, 80% and 50% of respective sums received by them. If total sum left with three NGOs is Rs. 6000, then find the income of man.Solution
Let the income of the man be Rs. x Therefore, sum donated to NGO βAβ = Rs. 0.20x Sum left with NGO βAβ = 0.25 Γ 0.20x = Rs. 0.05x Sum donated to NGO βBβ = Rs. 0.15x Sum left with NGO βBβ = 0.2 Γ 0.15x = Rs. 0.03x Sum donated to NGO βCβ = Rs. 0.24x Sum left with NGO βCβ = 0.5 Γ 0.24x = Rs. 0.12x According to the question, 0.05x + 0.03x + 0.12x = 6000 Or, 0.2x = 6000 Or, x = 6000/0.2 = 30000 Therefore, income of man = Rs. 30000
15(2/9) + 11(2/9) + 17(1/9) + 13(4/9) = ?
25% of 1000 + 10% of 150 β 22 Γ ? = 45
1885 ÷ 64.98 + 7.29 + ? = 69.09
βAβ and βBβ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, βAβ withdrew 25% of his initial investment...
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
What value should come in place of (?) question mark.
β2025 β β729 + (24 Γ 32) Γ· 6 = ?
What will come in the place of question mark (?) in the given expression?
(30% of 1200 + 50% of 3200) Γ· 98 = ?
(?) + (35)2 = (140)2 – (80)2 + 20% of 5480
7292/3 = ?