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      Question

      The total strength of school A is 20% more than that of

      school B. In school A and B, out of total number of students, 20% and 50% respectively are girls. The number of boys in school A is how much percent more/less than that in school B?
      A 85% Correct Answer Incorrect Answer
      B 92% Correct Answer Incorrect Answer
      C 60% Correct Answer Incorrect Answer
      D 70% Correct Answer Incorrect Answer

      Solution

      Let the total number of students in school B be ‘x’. Therefore, total number of students in school A = 1.2x Number of boys in school A = 0.80 × 1.2x = 0.96x Number of boys in school B = 0.5x Required % = [(0.96x – 0.5x)/0.5x] × 100 = 92%

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