Question
The total strength of school A is 20% more than that of
school B. In school A and B, out of total number of students, 30% and 40% respectively are girls. The number of boys in school A is how much percent more/less than that in school B?Solution
Let the total number of students in school B be ‘x’. Therefore, total number of students in school A = 1.2x Number of boys in school A = 0.70 × 1.2x = 0.84x Number of boys in school B = 0.6x Required % = [(0.84x – 0.6x)/0.6x] × 100 = 40%
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x² + 11x + 12 = 0
II. 2y² + 19y + 45 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
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