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      Question

      Find the smallest natural number which when divided by

      ‘6’, ‘8’ and ‘9’, leaves a remainder ‘5’ in each case.
      A 49 Correct Answer Incorrect Answer
      B 41 Correct Answer Incorrect Answer
      C 57 Correct Answer Incorrect Answer
      D 77 Correct Answer Incorrect Answer

      Solution

      LCM of (6, 8 and 9) = 72 So, required number = 72 + 5 = 77

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