Question
Find the unit digit of (8357 - 3).
Solution
Cyclicity of 3 = 3, 9, 7, 1, 3 Hence, we can see the last digits repeat themselves after every power of '4'. So, unit digit of 8357 = units digit of 3(56 + 1) = 3
{Since, (56/4) = 14} So, unit digit of 8357 - 3
= unit digit of 3 - 3
= 3 - 3 = 0
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