Question
The sum of three numbers is 130. If the ratio of
smallest number to largest number is 1:6, and that of smallest number to second smallest number is 1:3, then find the largest number.Solution
Let the smallest number be 'x' So, second smallest number = 3x And largest number = x Ă— 6 = 6x ATQ: 3x + 6x + x = 130 Or,
10x = 130 So,
x = 13 So, largest number = 13 Ă— 6 = 78
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