Question
Find the smallest positive integer which when divided by
5, 7 and 9 leaves a remainder 4 in each case.Solution
If N leaves remainder 4 when divided by 5, 7, 9, then N − 4 is divisible by all 5, 7, 9. LCM(5,7,9): 5 = 5 7 = 7 9 = 3² LCM = 5 × 7 × 3² = 5 × 7 × 9 = 315 So N − 4 = 315k ⇒ N = 315k + 4 Smallest positive N when k = 1: N = 315 × 1 + 4 = 319 Check: 319 ÷ 5 → remainder 4 319 ÷ 7 → 7×45 = 315, remainder 4 319 ÷ 9 → 9×35 = 315, remainder 4 Answer: 319.
Which of the following box is kept immediately below box B?
Answer the questions based on the information given below.
Six persons R, S, T, U, V, and W lives in a six- building floor such that the bottom...
F lives to the north east of ___.
Who among the following person lives immediate above flat of G?
Which of the following persons work in Jaipur?
On which of the following month and date does F participate?
As many persons completed between D and B is same as between H and ___.
Who among the following lives on the fifth floor?
Who among the following has lower price bike than U?
How many person was born before B?
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