Question
Find the sum of digits of the largest three-digit
number that leaves 7 as remainder when divided by 8, 5 and 9.Solution
ATQ, LCM of (8, 5 and 9) = 360 Largest 3-digit number divisible by 360 = 360 × 2 = 720 So, N = 720 + 7 = 727 Sum of digits of 'N' = 7 + 2 + 7 = 16
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