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      Question

      Find the difference between minimum and maximum value

      of 'g' such that '9g5621' is always divisible by 3.
      A 8 Correct Answer Incorrect Answer
      B 9 Correct Answer Incorrect Answer
      C 6 Correct Answer Incorrect Answer
      D 5 Correct Answer Incorrect Answer

      Solution

      A number is divisible by 3 when the sum of its digits is divisible by 3.
      Sum of digits of '9g5621' = (9 + g + 5 + 6 + 2 + 1) = g + 23.
      So, g + 23 should be divisible by 3.
      Possible values of 'g' = 2, 5, 8
      Minimum value of 'g' = 2
      Maximum value of 'g' = 8
      Required difference = 8 – 2 = 6

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