Question
‘N’ is the largest three-digit number that when divided by 6, 10 and 15 leaves a remainder 2. Find the sum of its digits.
Solution
ATQ, LCM of (6, 10 and 15) = 30 Largest 3-digit number divisible by 30 = 30 × 33 = 990 So, N = 990 + 2 = 992 Sum of digits of 'N' = 9 + 9 + 2 = 20
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