Question

Find the highest value of (x + y) if '7x482y6' is divisible

Q: Answer-Find the highest value of (x + y) if '7x482y6' is divisible by 12.

ATQ,A number is divisible by 12 if it is divisible by both 3 and 4.A number is divisible by 4 if the last two digits of the number form a number divisible by 4.y6 is divisible by 4 when y 0, 2, 4, 6 or 8.Since we need the highest value, so y 8.A number is divisible by 3 if the sum of all its digits is divisible by 3.7 x 4 8 2 8 6 35 x must be divisible by 3.So, x 1, 4 or 7.Since we need the highest value, so x 7.Thus, required value 7 8 15.