Question
Find the highest value of (x + y) if '7x482y6' is divisible
by 12.Solution
ATQ,
A number is divisible by 12 if it is divisible by both 3 and 4.
A number is divisible by 4 if the last two digits of the number form a number divisible by 4.
'y6' is divisible by 4 when 'y' = 0, 2, 4, 6 or 8.
Since we need the highest value, so 'y' = 8.
A number is divisible by 3 if the sum of all its digits is divisible by 3.
(7 + x + 4 + 8 + 2 + 8 + 6) = (35 + x) must be divisible by 3.
So, 'x' = 1, 4 or 7.
Since we need the highest value, so 'x' = 7.
Thus, required value = 7 + 8 = 15.
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