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    Question

    Find the highest value of (x + y) if '7x482y6' is divisible

    by 12.
    A 17 Correct Answer Incorrect Answer
    B 15 Correct Answer Incorrect Answer
    C 25 Correct Answer Incorrect Answer
    D 19 Correct Answer Incorrect Answer

    Solution

    ATQ,

    A number is divisible by 12 if it is divisible by both 3 and 4.

    A number is divisible by 4 if the last two digits of the number form a number divisible by 4.

    'y6' is divisible by 4 when 'y' = 0, 2, 4, 6 or 8.

    Since we need the highest value, so 'y' = 8.

    A number is divisible by 3 if the sum of all its digits is divisible by 3.

    (7 + x + 4 + 8 + 2 + 8 + 6) = (35 + x) must be divisible by 3.

    So, 'x' = 1, 4 or 7.

    Since we need the highest value, so 'x' = 7.

    Thus, required value = 7 + 8 = 15.

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