Question
If the product of three consecutive natural numbers is 336,
then find their total sum.Solution
ATQ,
Let the three natural numbers be ‘a’, ‘b’, and ‘c’.
ATQ,
a × b × c = 336
336 = 6 × 7 × 8
So, the three consecutive natural numbers are 6, 7, and 8
So, the required sum = 6 + 7 + 8 = 21
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