Question
A number when divided by 45 leaves 38 as remainder. If the
same number is divided by 15, the remainder would be:Solution
ATQ,
Let the number be β45x + 38β
We know that 45 is divisible by 15, so 45x will also be divisible by 15.
Remainder obtained when 38 is divided by 15 = 8
So, required remainder = 8
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