Question
What is the average of first 26 multiples of
2.6?Solution
First term = 2.6 x 1 = 2.6 Last term = 2.6 x 26 = 67.6 Required average = (2.6 + 67.6)/2 = 35.1
? = (25% of 20% of 800) Γ 8 β 25% of 260
(1/5){(2/5) Γ 400 + 20% of 150} = ?Β
(β 196 x β 36 x β 100) = ?% of 200
Find the value of 45 - 3 x (4 of 6 + 12 Γ· 3 Γ 6 β 4 Γ 5) + 6.
75% of 65% of 7/5 of 2420 = ?
30% of 60% of 1800 + 13 Γ 14 = (? Γ· 75) Γ 5
(117 + 93 - 10) Γ· 40 = ? - 12 X 2
30% of 180 + 248 Γ· ? - β256 = 102
345 = β2704 Γ· (?% of 104) + 7 3
β0.49 + β6.25 + β1.44 + β1.21 =? % of 125