Question
Instead of multiplying a number by 0.9, a student
accidentally used 9. His result turned out to be 3510 more than the actual result. What is the original number? (Calculate approximate number)Solution
ATQ,
Let original number be ‘x’
So, 9x – 0.9x = 3510
Or, 8.1x = 3510
Or, x = 433.33 or 433 approx.
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
[(√2024.85 ÷ 3.01) + (35.76 ÷ 11.92)]² × (3/4 of 39.99) = ?
Solve the following expression and calculate the approximate value.
398% of 388 + 129% of 323.89 – 430.93
The average of 5 positive integers was initially computed as 30. However, it was discovered later that an error had occurred duri...
25.11% of 239.99 + √143.97 ÷ 12.02 = ?
15.1 + 3.97 – 9.07 × 1.96 = √?Â
(16.16 ×  31.98) + 24.15% of 649.99 = ? + 124.34
157.78% of 4820 + 92.33% of 2840 = ? + 115.55% of 1980
(699.88% of 32) + (80.44% of 400.23) = ? + (11.67)2
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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