Question
Solve the following equation: 48 Γ· [35 β {30
β (31 β 26 Γ· 2 Γ 4)}]Solution
48 Γ· [35 β {30 β (31 β 26 Γ· 2 Γ 4)}] =48 Γ· [35 β {30 β (31 β 52)}] =48 Γ· [35 β {30 +21}] =48 Γ· [35 β 51] =48 Γ· [-16] = -3.
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Β Β
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